why this program goes to infinite loop #include<stdio.h&g...

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Question by madhur
Submitted on 8/19/2003
Related FAQ: Objective-C FAQ
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why this program goes to infinite loop #include<stdio.h> #include<conio.h>. int arr[10]; int x; void main(void) { for(x=1;x<=10;x++) arr[x]=-100 getch(); }

Answer by max
Submitted on 5/2/2004
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Because of a bug in it. In C/C++/Obj-C and others, arrays starts at pos 0 not 1, your "for" statement should be for(x=0;x<9;x++) As for the fact it goes into loop (instead of a crash) is compiler related (or better global variables storage related). What happens here is that when writing arr[10]=-100 you're actually overwriting the location where x is stored (that is right after your arr given the declaration) so making x=-100, at this point the next loop will go to arr[-100] writing back to arr[9], and then again restarting. You are lucky there was not important data between location arr[-100] and arr[9], it there were, a crash would have been more than probable.

Answer by max
Submitted on 5/2/2004
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Sorry about the again faulty correction The fix for the loop is: for(x=0;x<=9;x++) or for(x=0;x<10;x++) Sorry 'bout that.

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