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...compare values in a row of 4-columns, (all numbers...

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Question by bksys
Submitted on 12/11/2003
Related FAQ: comp.lang.awk FAQ
Rating: Rate this question: Vote
How can I compare values in a row of 4-columns, (all numbers and of varied field sizes), and print the field with maximum value under its column header?


Answer by Gus
Submitted on 8/26/2004
Rating: Not yet rated Rate this answer: Vote
I'm not sure if the column headers are in the file or not -- if they are, uncomment the three commented lines below.  Otherwise, set the hdr array in the BEGIN clause.

{
  if (NR==1) {
#    for (i=1; i<5; i++)
#      hdr[i]=$(i)
#  } else if (NR ==2) {
    for (i=1; i<5; i++)
      max[i]=$(i)
  } else {
    for (i=1; i<5; i++)
      if ($(i) > max[i])
        max[i]=$(i)
   }

END {
  for (i=1; i<5; i++) {
    len[i]=length(""max[i])
    if (length(hdr[i])>len[i])
      len[i]=length(hdr[i])
  }
  for (i=1; i<5; i++)
    printf "%"len[i]"s ", hdr[i]
  printf "\n"
  for (i=1; i<5; i++)
    printf "%"len[i]"s ", max[i]
}

 

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