Simple question I hope. I am trying to get awk to look at...

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Question by DAVE
Submitted on 2/12/2004
Related FAQ: comp.lang.awk FAQ
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Simple question I hope. I am trying to get awk to look at $3 and if it has an asterisk (), then print $4 instead. I used the code: awk '{ print $3 } $3~/""/ { print $4 }' It still prints $3 even if the line has an asterisk in it. Is this not how you do it? Is there an "unless" option?

Answer by obrienpx
Submitted on 3/11/2004
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Try: awk '$3 !~ /\/ { print $3 } $3~/\/ { print $4 }'

Answer by piko
Submitted on 3/23/2004
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try { if $3=="*" { print $4; } else { print $3; } }

Answer by jeex
Submitted on 10/6/2004
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You can also try: awk '{if ($3=="*") $3=$4; print $3}'

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