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sci.math FAQ: The Monty Hall Problem


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Archive-name: sci-math-faq/montehall
Last-modified: February 20, 1998
Version: 7.5

     _________________________________________________________________
   
                            The Monty Hall problem
                                       
   This problem has rapidly become part of the mathematical folklore.
   
   The American Mathematical Monthly, in its issue of January 1992,
   explains this problem carefully. The following are excerpted from that
   article.
   
   Problem:
   
   A TV host shows you three numbered doors (all three equally likely),
   one hiding a car and the other two hiding goats. You get to pick a
   door, winning whatever is behind it. Regardless of the door you
   choose, the host, who knows where the car is, then opens one of the
   other two doors to reveal a goat, and invites you to switch your
   choice if you so wish. Does switching increases your chances of
   winning the car?
   
   If the host always opens one of the two other doors, you should
   switch. Notice that 1/3 of the time you choose the right door (i.e.
   the one with the car) and switching is wrong, while 2/3 of the time
   you choose the wrong door and switching gets you the car.
   
   Thus the expected return of switching is 2/3 which improves over your
   original expected gain of 1/3.
   
   Even if the hosts offers you to switch only part of the time, it pays
   to switch. Only in the case where we assume a malicious host (i.e. a
   host who entices you to switch based in the knowledge that you have
   the right door) would it pay not to switch.
   
   There are several ways to convince yourself about why it pays to
   switch. Here's one. You select a door. At this time assume the host
   asks you if you want to switch before he opens any doors. Even though
   the odds that the door you selected is empty are high (2/3), there is
   no advantage on switching as there are two doors, and you don't know
   thich one to switch to. This means the 2/3 are evenly distributed,
   which as good as you are doing already. However, once Monty opens one
   of the two doors you selected, the chances that you selected the right
   door are still 1/3 and now you only have one door to choose from if
   you switch. So it pays to switch.
   
      References
      
   L. Gillman The Car and the Goats American Mathematical Monthly,
   January 1992, pp. 3-7.
-- 
Alex Lopez-Ortiz                                         alopez-o@unb.ca
http://www.cs.unb.ca/~alopez-o                       Assistant Professor	
Faculty of Computer Science                  University of New Brunswick

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