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Top Document: Invariant Galilean Transformations On All Laws Previous Document: 8. What does sci.math have to say about x0'=x0-vt? Next Document: 10. But Isn't (x'-x.c')=(x-x.c) Actually Two Transformations? See reader questions & answers on this topic! - Help others by sharing your knowledge
That idea is one of the most idiotic to come up, and it does
so frequently. And in a number of guises.
The idea being that x.c' <> x.c-vt, with x.c being what
we have called x0 above; the notation makes no difference.
Some crackpots have managed to maintain that position even
after graphs have illustrated that such an idea means that
after a while a circle center represented by x.c' could be
outside the circle.
The leading crackpot just make that explicit, as far as
one can tell from his befuddled post in response to a line
about "active" transforms, which are actually moving body
situations, not coordinate transformations:
--------------------------------------------------------------------
e>An active transform is not a coordinate transform, ...
Right, it is a transform of the center (in the opposite direction)
done to effect the change of coordinates without a coordinate
transform. ...
E: Transform of the center? Center of a circle?
He really is saying a circle center moves in
the opposite direction of the circle! Right?
--------------------------------------------------------------------
If r=10 and x.c was at x.c=0, then the points on the circle
(10,0), (-10,0), (0,10) and (0,-10) could at some time become
(-10,0), (-30,0), (-20,10), and (-20,-10), but with x.c'=x.c,
the circle center would be at (0,0) still! The circle is here
but its center is way, way over there! Indeed, although a change
of coordinate systems is not movement of any object described in
the coordinates, the x.c'=x.c crackpottery is tantamount to the
circle staying put but the center moving away. Or vice versa.
User Contributions:Top Document: Invariant Galilean Transformations On All Laws Previous Document: 8. What does sci.math have to say about x0'=x0-vt? Next Document: 10. But Isn't (x'-x.c')=(x-x.c) Actually Two Transformations? Single Page [ Usenet FAQs | Web FAQs | Documents | RFC Index ] Send corrections/additions to the FAQ Maintainer: Thnktank@concentric.net (Eleaticus)
Last Update March 27 2014 @ 02:12 PM
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