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# Invariant Galilean Transformations On All LawsSection - 5. Transformations on Generalized Coordinate Laws

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```The traditional Gallilean transform is correct:

t'   = t

x'   = x - vt.

But remember this: a transform of x doesn't effect
just some values of x, but all of them, whether they
are in the formula or not.  This is important if you
want to do things right. The crackpot position is
strongly against this sci.math verified position, and
the apparently standard coordinate pseudo-transformation
they suggest is perhaps the result. {See Table of
Contents.]

Let's use a simple equation: x^2 + y^2 = r^2, which is
the formula for a circle with radius r, centered at a
location where x=0.

But what if the circle center isn't at x=0?  Well, we'd
want to use the form analytic geometry, vector algebra,
and elementary measurement theory tells us to use, a form
where we make explicit just where the circle center is,
even if it is at x=x0=0:

(x-x0)^2 + (y-y0)^2 = r^2.

The circle center coordinate, x0, is an x-axis coordinate,
just like all the x-values of points on the circle.

So, in proper generalized cartesian coordinate forms
of laws/equations we want to transform every occurence
of x and x0 - by whatever name we call it: x.c, x_e,
whatever.

So, what is the transformed version of (x-x0)?  Why,
(x'-x0'); both x and x0 are x-coordinates, and every
x-coordinate has a new value on the new axis.

So, what is the value of (x'-x0') in terms of the original
x data?

From the transform equations we see that x'=x-vt, which
is also true for x0'=x0-vt:

(x'-x0')=[ (x-vt)-(x0-vt) ]=(x-x0).

In other words, when we use the generalized coordinate form
specified by analytic geometry, we find that the value of
(x'-x0') does not depend on either time or velocity in any
way, shape, form, or fashion.

Similarly for (y-y0).

We can treat time the same way if necessary: (t-t0).

The above is a proof that any equation in x,y,z,t is
invariant under the galilean transforms. Just use the
generalized coordinate form, with (x-x0)/etc, in the
transformation process, not the incompetently selected
privileged form, with just x/etc.

[The form is "privileged" because it assumes the circle
center, point of emission, whatever, is at the origin of
the axes instead at some less convenient point. After
transform the coordinate(s) of the circle center/origin
are also changed but the privileged form doesn't make
this explicit and screws up the calculations, which
should be based on (x'-x0') but are calculated as (x'-0).]

The value of (x'-x0') is the same as (x-x0).  That makes
sense.

Draw a circle on a piece of paper, maybe to the right
side of the paper. On a transparent sheet, draw x and y
coordinate axes, plus x to the right, plus y at the top.

Place this axis sheet so the y-axis is at the left side
of the circle sheet.

Now answer two questions after noting the x-coordinate of
the circle center and then moving the axis sheet to the right:

(a) did the circle change in any way because you moved
the axis sheet (ie because you transformed the coordin-
nate axis)?

(b) did the coordinate of the circle center change?

The circle didn't change [although SR will say it did];
that means that (x'-x0') does indeed equal (x-x0).

The coordinate of the circle center did change, and it
changed at the same rate (-vt) as did every point on
the circle.   That means that x0'<>x0, and the fact the
circle center didn't change wrt the circle, means that
the relationship of x0' with x0 is the same as that of
any x' on the circle with the corresponding x: x'=x-vt;
x0'=x0-vt.

This is to prepare you for the True Believer crackpots that
say 'constant' coordinates can't be transformed; some even
say they aren't coordinates. These crackpots include some
that brag about how they were childhood geniuses, btw.

QED: The galilean transformation for any law on
generalized Cartesian coordinates is invariant under
the Galilean transform.

The use of the privileged form explains HOW the transformed
equation can be messed up, the next Subject explains what
the screwed up effect of the transform is, and how use
of the generalized form corrects the screwup.

```

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Top Document: Invariant Galilean Transformations On All Laws
Previous Document: 4. The Encyclopedia Brittanica Incompetency.
Next Document: 6. The data scale degradation absurdity.

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Last Update March 27 2014 @ 02:12 PM